tag | c2b80af3e94ab7b7a8b58c3985a09532baf17982 | |
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tagger | The Android Open Source Project <initial-contribution@android.com> | Mon Dec 04 10:10:42 2023 -0800 |
object | 131042402ea3d5403761b71e3bf127ad1d842039 |
Android Security 14.0.0 Release 3 (10993244)
commit | 131042402ea3d5403761b71e3bf127ad1d842039 | [log] [tgz] |
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author | Android Build Coastguard Worker <android-build-coastguard-worker@google.com> | Fri Sep 23 01:13:10 2022 +0000 |
committer | Android Build Coastguard Worker <android-build-coastguard-worker@google.com> | Fri Sep 23 01:13:10 2022 +0000 |
tree | 1658cb90958498bab43d7ddd0aa2ef61be41ff5d | |
parent | 8640dcfecb8596d172114e2ecba01f4887346c13 [diff] | |
parent | 19c5e177c75bcc802f5ac1c6e5b2db1d64f2e280 [diff] |
Snap for 9094779 from 19c5e177c75bcc802f5ac1c6e5b2db1d64f2e280 to udc-release Change-Id: I319f0beecf4ac8a65a5e71619b4367a9de37a900
Python 3.3+'s ipaddress for Python 2.6, 2.7, 3.2.
This repository tracks the latest version from cpython, e.g. ipaddress from cpython 3.8 as of writing.
Note that just like in Python 3.3+ you must use character strings and not byte strings for textual IP address representations:
>>> from __future__ import unicode_literals >>> ipaddress.ip_address('1.2.3.4') IPv4Address(u'1.2.3.4')
or
>>> ipaddress.ip_address(u'1.2.3.4') IPv4Address(u'1.2.3.4')
but not:
>>> ipaddress.ip_address(b'1.2.3.4') Traceback (most recent call last): File "<stdin>", line 1, in <module> File "ipaddress.py", line 163, in ip_address ' a unicode object?' % address) ipaddress.AddressValueError: '1.2.3.4' does not appear to be an IPv4 or IPv6 address. Did you pass in a bytes (str in Python 2) instead of a unicode object?