tag | 30b9fff47c0990d8b0c1359b17759c860668f5a3 | |
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tagger | The Android Open Source Project <initial-contribution@android.com> | Mon Aug 15 11:07:58 2022 -0700 |
object | c78dacaaa4c4309b937b7d7249f08f7b8afe9ffb |
Android security 13.0.0 release 1
commit | c78dacaaa4c4309b937b7d7249f08f7b8afe9ffb | [log] [tgz] |
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author | android-build-team Robot <android-build-team-robot@google.com> | Thu Jun 03 03:04:22 2021 +0000 |
committer | android-build-team Robot <android-build-team-robot@google.com> | Thu Jun 03 03:04:22 2021 +0000 |
tree | 994f7da7a7f4f482fcf3528bbe7ba101c62806b8 | |
parent | b2007baf7a2821c539b3fad5fdaa414854c97b08 [diff] | |
parent | 8640dcfecb8596d172114e2ecba01f4887346c13 [diff] |
Snap for 7418644 from 8640dcfecb8596d172114e2ecba01f4887346c13 to tm-release Change-Id: I55b893292d034568a224a014abc516a65db920f3
Python 3.3+'s ipaddress for Python 2.6, 2.7, 3.2.
This repository tracks the latest version from cpython, e.g. ipaddress from cpython 3.8 as of writing.
Note that just like in Python 3.3+ you must use character strings and not byte strings for textual IP address representations:
>>> from __future__ import unicode_literals >>> ipaddress.ip_address('1.2.3.4') IPv4Address(u'1.2.3.4')
or
>>> ipaddress.ip_address(u'1.2.3.4') IPv4Address(u'1.2.3.4')
but not:
>>> ipaddress.ip_address(b'1.2.3.4') Traceback (most recent call last): File "<stdin>", line 1, in <module> File "ipaddress.py", line 163, in ip_address ' a unicode object?' % address) ipaddress.AddressValueError: '1.2.3.4' does not appear to be an IPv4 or IPv6 address. Did you pass in a bytes (str in Python 2) instead of a unicode object?