dynamic_debug: make netdev_dbg() call __netdev_printk()
Previously, if dynamic debug was enabled netdev_dbg() was using
dynamic_dev_dbg() to print out the underlying msg. Fix this by making
sure netdev_dbg() uses __netdev_printk().
Cc: David S. Miller <davem@davemloft.net>
Signed-off-by: Jason Baron <jbaron@redhat.com>
Signed-off-by: Greg Kroah-Hartman <gregkh@suse.de>
diff --git a/include/linux/dynamic_debug.h b/include/linux/dynamic_debug.h
index 843cb9e..feaac1e 100644
--- a/include/linux/dynamic_debug.h
+++ b/include/linux/dynamic_debug.h
@@ -47,6 +47,13 @@
const char *fmt, ...)
__attribute__ ((format (printf, 3, 4)));
+struct net_device;
+
+extern int __dynamic_netdev_dbg(struct _ddebug *descriptor,
+ const struct net_device *dev,
+ const char *fmt, ...)
+ __attribute__ ((format (printf, 3, 4)));
+
#define dynamic_pr_debug(fmt, ...) do { \
static struct _ddebug descriptor \
__used \
@@ -67,6 +74,16 @@
__dynamic_dev_dbg(&descriptor, dev, fmt, ##__VA_ARGS__); \
} while (0)
+#define dynamic_netdev_dbg(dev, fmt, ...) do { \
+ static struct _ddebug descriptor \
+ __used \
+ __attribute__((section("__verbose"), aligned(8))) = \
+ { KBUILD_MODNAME, __func__, __FILE__, fmt, __LINE__, \
+ _DPRINTK_FLAGS_DEFAULT }; \
+ if (unlikely(descriptor.enabled)) \
+ __dynamic_netdev_dbg(&descriptor, dev, fmt, ##__VA_ARGS__);\
+ } while (0)
+
#else
static inline int ddebug_remove_module(const char *mod)