[CRYPTO] all: Pass tfm instead of ctx to algorithms
Up until now algorithms have been happy to get a context pointer since
they know everything that's in the tfm already (e.g., alignment, block
size).
However, once we have parameterised algorithms, such information will
be specific to each tfm. So the algorithm API needs to be changed to
pass the tfm structure instead of the context pointer.
This patch is basically a text substitution. The only tricky bit is
the assembly routines that need to get the context pointer offset
through asm-offsets.h.
Signed-off-by: Herbert Xu <herbert@gondor.apana.org.au>
diff --git a/crypto/md4.c b/crypto/md4.c
index a2d6df5..c1bc71b 100644
--- a/crypto/md4.c
+++ b/crypto/md4.c
@@ -152,9 +152,9 @@
md4_transform(ctx->hash, ctx->block);
}
-static void md4_init(void *ctx)
+static void md4_init(struct crypto_tfm *tfm)
{
- struct md4_ctx *mctx = ctx;
+ struct md4_ctx *mctx = crypto_tfm_ctx(tfm);
mctx->hash[0] = 0x67452301;
mctx->hash[1] = 0xefcdab89;
@@ -163,9 +163,9 @@
mctx->byte_count = 0;
}
-static void md4_update(void *ctx, const u8 *data, unsigned int len)
+static void md4_update(struct crypto_tfm *tfm, const u8 *data, unsigned int len)
{
- struct md4_ctx *mctx = ctx;
+ struct md4_ctx *mctx = crypto_tfm_ctx(tfm);
const u32 avail = sizeof(mctx->block) - (mctx->byte_count & 0x3f);
mctx->byte_count += len;
@@ -193,9 +193,9 @@
memcpy(mctx->block, data, len);
}
-static void md4_final(void *ctx, u8 *out)
+static void md4_final(struct crypto_tfm *tfm, u8 *out)
{
- struct md4_ctx *mctx = ctx;
+ struct md4_ctx *mctx = crypto_tfm_ctx(tfm);
const unsigned int offset = mctx->byte_count & 0x3f;
char *p = (char *)mctx->block + offset;
int padding = 56 - (offset + 1);